The Islamic State, West African Province (ISWAP) has revealed how the former Boko Haram leader, Abubakar Shekau died during a deadly confrontation between the two terrorist groups.
ISWAP, according to an internal message from ISWAP leader, Abu Musab Albarnawi, stated that Shekau committed suicide by detonating a bomb after refusing to surrender following the invasion of his hideout on Wednesday, May 19.
A report by HumAngle, said in his address, which was delivered in Hausa, Albarnawi described Shekau as “the leader of disobedience and corruption” and said his fighters rejoiced over his death.
He said the former terrorist leader, who took over after the death of Boko Haram founder, Mohammed Yusuf in 2009, was apprehended “in the most humiliating manner.”
This was someone who committed unimaginable terrorism. How many has he wasted? How many has he killed? How many has he terrorised? But Allah left him alone and prolonged his life. When it was time, Allah set out brave soldiers after receiving orders from Amirul Muminin (leader of the believers),” he said.
It was reported that the ISWAP, which broke away from Shekau’s Boko Haram faction in 2016, disagreed with the late extremist leader over his excessive use of force, against other Muslims and women.
According to Albarnawi, the interim leader of the Islamic State of Iraq and Syria (ISIS) ordered them to take action on Shekau for deviating and killing “believers.”
ISWAP fighters then took their arms, travelled through the Sahara, went into Shekau’s enclave and engaged in a gun battle with his followers.